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# numpy.right_shift

`numpy.``right_shift`(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'right_shift'>

  Shift the bits of an integer to the right.

  Bits are shifted to the right x2. Because the internal representation of numbers is in binary format, this operation is equivalent to dividing x1 by `2**x2`.

  Parameters: | x1 : array_like, int Input values. x2 : array_like, int Number of bits to remove at the right of x1. out : ndarray, None, or tuple of ndarray and None, optional A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs. where : array_like, optional Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone. **kwargs For other keyword-only arguments, see the ufunc docs.
  Returns: | out : ndarray, int Return x1 with bits shifted x2 times to the right.

  See also

  `left_shift`
    Shift the bits of an integer to the left.
  `binary_repr`
    Return the binary representation of the input number as a string.

  Examples

      >>> np.binary_repr(10)
      '1010'
      >>> np.right_shift(10, 1)
      5
      >>> np.binary_repr(5)
      '101'

      >>> np.right_shift(10, [1,2,3])
      array([5, 2, 1])