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# numpy.cosh

`numpy.``cosh`(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'cosh'>

  Hyperbolic cosine, element-wise.

  Equivalent to `1/2 * (np.exp(x) + np.exp(-x))` and `np.cos(1j*x)`.

  Parameters: | x : array_like Input array. out : ndarray, None, or tuple of ndarray and None, optional A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs. where : array_like, optional Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone. **kwargs For other keyword-only arguments, see the ufunc docs.
  Returns: | out : ndarray Output array of same shape as x.

  Examples

      >>> np.cosh(0)
      1.0

  The hyperbolic cosine describes the shape of a hanging cable:

      >>> import matplotlib.pyplot as plt
      >>> x = np.linspace(-4, 4, 1000)
      >>> plt.plot(x, np.cosh(x))
      >>> plt.show()

  (Source code, png, pdf)