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# numpy.square

`numpy.``square`(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'square'>

  Return the element-wise square of the input.

  Parameters: | x : array_like Input data. out : ndarray, None, or tuple of ndarray and None, optional A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs. where : array_like, optional Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone. **kwargs For other keyword-only arguments, see the ufunc docs.
  Returns: | out : ndarray Element-wise x*x, of the same shape and dtype as x. Returns scalar if x is a scalar.

  See also

  `numpy.linalg.matrix_power`, `sqrt`, `power`

  Examples

      >>> np.square([-1j, 1])
      array([-1.-0.j,  1.+0.j])