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# numpy.expm1

`numpy.``expm1`(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'expm1'>

  Calculate `exp(x) - 1` for all elements in the array.

  Parameters: | x : array_like Input values. out : ndarray, None, or tuple of ndarray and None, optional A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs. where : array_like, optional Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone. **kwargs For other keyword-only arguments, see the ufunc docs.
  Returns: | out : ndarray Element-wise exponential minus one: `out = exp(x) - 1`.

  See also

  `log1p`
    `log(1 + x)`, the inverse of expm1.

  Notes

  This function provides greater precision than `exp(x) - 1` for small values of `x`.

  Examples

  The true value of `exp(1e-10) - 1` is `1.00000000005e-10` to about 32 significant digits. This example shows the superiority of expm1 in this case.

      >>> np.expm1(1e-10)
      1.00000000005e-10
      >>> np.exp(1e-10) - 1
      1.000000082740371e-10