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numpy.setxor1d

# numpy.setdiff1d

`numpy.``setdiff1d`(ar1, ar2, assume_unique=False)

  Find the set difference of two arrays.

  Return the sorted, unique values in ar1 that are not in ar2.

  Parameters: | ar1 : array_like Input array. ar2 : array_like Input comparison array. assume_unique : bool If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.
  Returns: | setdiff1d : ndarray Sorted 1D array of values in ar1 that are not in ar2.

  See also

  `numpy.lib.arraysetops`
    Module with a number of other functions for performing set operations on arrays.

  Examples

      >>> a = np.array([1, 2, 3, 2, 4, 1])
      >>> b = np.array([3, 4, 5, 6])
      >>> np.setdiff1d(a, b)
      array([1, 2])