#### Previous topic

scipy.misc.lena

#### Next topic

scipy.misc.pade

# scipy.misc.logsumexp

`scipy.misc.``logsumexp`(a, axis=None, b=None, keepdims=False)

  Compute the log of the sum of exponentials of input elements.

  Parameters: | a : array_like Input array. axis : None or int or tuple of ints, optional Axis or axes over which the sum is taken. By default axis is None, and all elements are summed. Tuple of ints is not accepted if NumPy version is lower than 1.7.0. New in version 0.11.0. keepdims : bool, optional If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the original array. New in version 0.15.0. b : array-like, optional Scaling factor for exp(a) must be of the same shape as a or broadcastable to a. New in version 0.12.0.
  Returns: | res : ndarray The result, `np.log(np.sum(np.exp(a)))` calculated in a numerically more stable way. If b is given then `np.log(np.sum(b*np.exp(a)))` is returned.

  See also

  `numpy.logaddexp`, `numpy.logaddexp2`

  Notes

  Numpy has a logaddexp function which is very similar to `logsumexp`, but only handles two arguments. logaddexp.reduce is similar to this function, but may be less stable.

  Examples

      >>> from scipy.misc import logsumexp
      >>> a = np.arange(10)
      >>> np.log(np.sum(np.exp(a)))
      9.4586297444267107
      >>> logsumexp(a)
      9.4586297444267107

  With weights

      >>> a = np.arange(10)
      >>> b = np.arange(10, 0, -1)
      >>> logsumexp(a, b=b)
      9.9170178533034665
      >>> np.log(np.sum(b*np.exp(a)))
      9.9170178533034647