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# scipy.fftpack.fftn

`scipy.fftpack.``fftn`(x, shape=None, axes=None, overwrite_x=False)

  Return multidimensional discrete Fourier transform.

  The returned array contains:

      y[j_1,..,j_d] = sum[k_1=0..n_1-1, ..., k_d=0..n_d-1]
         x[k_1,..,k_d] * prod[i=1..d] exp(-sqrt(-1)*2*pi/n_i * j_i * k_i)

  where d = len(x.shape) and n = x.shape. Note that `y[..., -j_i, ...] = y[..., n_i-j_i, ...].conjugate()`.

  Parameters: | x : array_like The (n-dimensional) array to transform. shape : tuple of ints, optional The shape of the result. If both shape and axes (see below) are None, shape is `x.shape`; if shape is None but axes is not None, then shape is `scipy.take(x.shape, axes, axis=0)`. If `shape[i] > x.shape[i]`, the i-th dimension is padded with zeros. If `shape[i] < x.shape[i]`, the i-th dimension is truncated to length `shape[i]`. axes : array_like of ints, optional The axes of x (y if shape is not None) along which the transform is applied. overwrite_x : bool, optional If True, the contents of x can be destroyed. Default is False.
  Returns: | y : complex-valued n-dimensional numpy array The (n-dimensional) DFT of the input array.

  See also

  `ifftn`

  Examples

      >>> from scipy.fftpack import fftn, ifftn
      >>> y = (-np.arange(16), 8 - np.arange(16), np.arange(16))
      >>> np.allclose(y, fftn(ifftn(y)))
      True