#### Previous topic

scipy.signal.firwin2

#### Next topic

scipy.signal.freqz

# scipy.signal.freqs

`scipy.signal.``freqs`(b, a, worN=None, plot=None)

  Compute frequency response of analog filter.

  Given the numerator b and denominator a of a filter, compute its frequency response:

              b[0]*(jw)**(nb-1) + b[1]*(jw)**(nb-2) + ... + b[nb-1]
      H(w) = -------------------------------------------------------
              a[0]*(jw)**(na-1) + a[1]*(jw)**(na-2) + ... + a[na-1]

  Parameters: | b : ndarray Numerator of a linear filter. a : ndarray Denominator of a linear filter. worN : {None, int}, optional If None, then compute at 200 frequencies around the interesting parts of the response curve (determined by pole-zero locations). If a single integer, then compute at that many frequencies. Otherwise, compute the response at the angular frequencies (e.g. rad/s) given in worN. plot : callable, optional A callable that takes two arguments. If given, the return parameters w and h are passed to plot. Useful for plotting the frequency response inside `freqs`.
  Returns: | w : ndarray The angular frequencies at which h was computed. h : ndarray The frequency response.

  See also

  `freqz`
    Compute the frequency response of a digital filter.

  Notes

  Using Matplotlib’s “plot” function as the callable for plot produces unexpected results, this plots the real part of the complex transfer function, not the magnitude. Try `lambda w, h: plot(w, abs(h))`.

  Examples

      >>> from scipy.signal import freqs, iirfilter

      >>> b, a = iirfilter(4, [1, 10], 1, 60, analog=True, ftype='cheby1')

      >>> w, h = freqs(b, a, worN=np.logspace(-1, 2, 1000))

      >>> import matplotlib.pyplot as plt
      >>> plt.semilogx(w, 20 * np.log10(abs(h)))
      >>> plt.xlabel('Frequency')
      >>> plt.ylabel('Amplitude response [dB]')
      >>> plt.grid()
      >>> plt.show()

  (Source code)